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Home | C (x , y) | Permutation | Fixes/Countin'theory

How many hands are there in omaha if u dont count suits (ex. (4diamonds,4hearts,5diamonds,5hearts=4clubs,4spads,5clubs,5hearts)?
 
With help from Brian Alspach i have made this website to show you how to answer this question.
 
The solution is as follows:
First of all if you count suit, there are C(52,4)= 270,725 hands
then you apply permutation
add all the fixes each permutation makes together
divide by the # of permutations (counting theory)
get # of starting hands

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